Author Topic: resistor for led  (Read 1093 times)

Offline chrisatpsu

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resistor for led
« on: January 23, 2012, »
i know i have calculators for resistor size...

and i know RJ explained this to me...  but it has escaped me...

to power a normal 20mA led with a regular resistor, what size resistor should i use wattage wise?
1/4 fine?  can i go smaller?
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Offline chrisatpsu

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Re: resistor for led
« Reply #1 on: January 23, 2012, »
oh yeah...  5v supply
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Offline rrowan

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Re: resistor for led
« Reply #2 on: January 23, 2012, »
1/4 watt resistor should be fine

btw: Are you just trying to raise you post per day stat?

LOL

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Offline chrisatpsu

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Re: resistor for led
« Reply #3 on: January 23, 2012, »
nope, just helping where i can, and asking for help when i need it  : )
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Offline pk

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Re: resistor for led
« Reply #4 on: January 23, 2012, »
The resistor will be dissipating less than 0.1 watt

Offline chrisatpsu

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Re: resistor for led
« Reply #5 on: January 23, 2012, »
would 1/8 watt be ok, or cutting it too close?
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Offline Dennis Cherry

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Re: resistor for led
« Reply #6 on: January 23, 2012, »
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would 1/8 watt be ok, or cutting it too close?

Stay with the 1/4 watt, it is small.
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Offline chrisatpsu

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Re: resistor for led
« Reply #7 on: January 23, 2012, »
so i have it written down (via a forum), how did you calculate the wattage?
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Offline rrowan

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Re: resistor for led
« Reply #8 on: January 23, 2012, »
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so i have it written down (via a forum), how did you calculate the wattage?

Ohms Law  ;D

P x I(squared) = watts

or Power times current (sq) =

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Offline chrisatpsu

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Re: resistor for led
« Reply #9 on: January 23, 2012, »
i feel like an idiot...   i actually knew that one!   lol
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Offline Dennis Cherry

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Re: resistor for led
« Reply #10 on: January 23, 2012, »
Anything you want to calculate in Ohm's Law.

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Offline rrawlings

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Re: resistor for led
« Reply #11 on: January 23, 2012, »
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so i have it written down (via a forum), how did you calculate the wattage?

Ohms Law  ;D

P x I(squared) = watts

or Power times current (sq) =

Rick R.

P=I(squared) x R

P = Watts