Well there are a lot of opinions out there!
Let's look at the spec the bulb is rated at 35W (35 watts) OK.
The wall plug is 12 VAC (12 volts alternating current).
The MR-16 is a DC (direct current) device.
A light bulb (filament type) will operate on either AC or DC.
Acording to ohms law P(power) = V (voltage) x I (amperes)
We have some given data power of the quartz halegeon bulb is 35W and the operating voltage is 12VAC.
So let's subsitute the given values into the formula 35w = 12 vac x I (amperes)
Let's drop the units we get 35= 12 x I
From algebra in high school we know that in the above fomula the equal sign means that either side of the equation must be equal.
What must we do to move the 12 to the left side of the equal sign. Answer is divide both sides by 12.
Therfore the equation look like 35/12 = (12 xI)/12
The equation looks like this 35/12= I
Do the division leaves 2.91 = I so the current needed is 2.91 amperes.
Can it work on a MR-16
yes but the wiki says 2.5 amps max the FET can handle it but watch the overall max current in the wiki on the MR-16.
Wally
wbe12345